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@@ -423,9 +423,9 @@ free carrier diffusion is neglected during and shortly after the laser
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excitation \cite{Van1987, Sokolowski2000}. In particular, from the
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Einstein formula $D = k_B T_e \tau/m^*$ $\approx$ (1-2)10$^5$ m/s
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(k$_B$ is the Boltzmann constant, T$_e$ is the electron temperature,
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-$\tau$=1~fs is the collision time, $m^*$ = 0.18$m_e$ is the effective
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+$\tau$=1~\textit{fs} is the collision time, $m^*$ = 0.18$m_e$ is the effective
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mass), where T$_e$ $\approx$ 2*10$^4$~K for N$_e$ close to N$_cr$. It
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-means that during the pulse duration ($\approx$ 50~fs) the diffusion
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+means that during the pulse duration ($\approx$ 50~\textit{fs}) the diffusion
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length will be around 5--10~nm for N$_e$ close to N$_cr$.
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\begin{figure}[ht!]
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@@ -597,9 +597,9 @@ license.
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whereas electric one (\textit{a1}) has $Q \approx$4. The larger
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particle supporting magnetic quadrupole resonance (\textit{b2})
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demonstrates \textit{Q} $\approx$ 40. As soon as the electromagnetic
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- wave period at $\lambda$~=~800~nm is 2.6~fs, we need about 10~fs
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- pulse to pump the electric dipole, 20~fs for the magnetic dipole, and
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- about 100~fs for the magnetic quadrupole.
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+ wave period at $\lambda$~=~800~nm is 2.6~\textit{fs}, we need about 10~\textit{fs}
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+ pulse to pump the electric dipole, 20~\textit{fs} for the magnetic dipole, and
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+ about 100~\textit{fs} for the magnetic quadrupole.
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According to these estimations, the first optical cycles taking place
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on few-femtosecond scale result in the excitation of the
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@@ -620,7 +620,7 @@ license.
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is still not high enough to affect significantly optical properties
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of the Si NP.
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- A number of optical cycles ($>$10 or $t>$25~fs) is necessary to
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+ A number of optical cycles ($>$10 or $t>$25~\textit{fs}) is necessary to
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achieve the stationary intensity pattern corresponding to the
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Mie-based intensity distribution at the \textit{'Stage $3$'} (see
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Fig.~\ref{fig3}). The EHP density are still relatively not high to
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