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Update on Overleaf.

Anonymous 7 years ago
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17b71df82b
1 changed files with 2 additions and 2 deletions
  1. 2 2
      main.tex

+ 2 - 2
main.tex

@@ -526,8 +526,8 @@ license.
  distribution during the \textit{fs} pulse, we introduced another
  distribution during the \textit{fs} pulse, we introduced another
  asymmetry factor
  asymmetry factor
  $G_{N_e} = (N_e^{front}-N_e^{back})/(N_e^{front}+N_e^{back})$
  $G_{N_e} = (N_e^{front}-N_e^{back})/(N_e^{front}+N_e^{back})$
- indicating the relationship between the average EHP densities in the front and in the back halves of the NP, defined as $N_e^{front}=\int_{(z>0)} {N_e}d{\mathrm{v}}$ and
- $N_e^{back}=\int_{(z<0)} {N_e}d{\mathrm{v}}$. In this way, $G_{N_e} = 0$ corresponds to the quasi-homogeneous case and the assumption of the
+ indicating the relationship between the average EHP densities in the front and in the back halves of the NP, defined as $N_e^{front}=2\int_{(z>0)} {N_e}d{\mathrm{v}}/V$ and
+ $N_e^{back}=2\int_{(z<0)} {N_e}d{\mathrm{v}}/V$, where $V = \frac{4}{3}\pi{R}^3$ is the volume of the nanosphere. In this way, $G_{N_e} = 0$ corresponds to the quasi-homogeneous case and the assumption of the
  NP homogeneous EHP distribution can be made to investigate the
  NP homogeneous EHP distribution can be made to investigate the
  optical response of the excited Si NP. When $G_{N_e}$ significantly
  optical response of the excited Si NP. When $G_{N_e}$ significantly
  differs from $0$, this assumption, however, could not be
  differs from $0$, this assumption, however, could not be